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Proof step 27 from proof abs-pos (previous step)

abs(i) / gcd(i, j) ≠ 0 ∧ 0 < j / gcd(i, j), 0 < j ⊦ i = 0, j = 0, (abs(i) / gcd(i, j)) / gcd(abs(i) / gcd(i, j), j / gcd(i, j)) = rational(abs(i), j).num

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 28:
0 < j, 0 < j / gcd(i, j) ⊦ i = 0, j = 0, (abs(i) / gcd(i, j)) / gcd(abs(i) / gcd(i, j), j / gcd(i, j)) = rational(abs(i), j).num, abs(i) / gcd(i, j) = 0

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)