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Proof step 6 from proof add-asso (previous step)

∃ i, j. rj = rational(i, j) ∧ 0 < j, 0 < j ⊦ (rational(i, j) + rj) + rj0 = rational(i, j) + rj + rj0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
0 < j, 0 < j0 ⊦ (rational(i, j) + rational(i0, j0)) + rj0 = rational(i, j) + rational(i0, j0) + rj0

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)