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Proof step 9 from proof add-asso (previous step)

∃ i, j. rj0 = rational(i, j) ∧ 0 < j, 0 < j, 0 < j0 ⊦ (rational(i, j) + rational(i0, j0)) + rj0 = rational(i, j) + rational(i0, j0) + rj0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
0 < j, 0 < j0, 0 < j1 ⊦ (rational(i, j) + rational(i0, j0)) + rational(i1, j1) = rational(i, j) + rational(i0, j0) + rational(i1, j1)

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)