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Proof step 15 from proof add-def-03 (previous step)

j2 < 0, j1 < 0, j2 < 0 ⊦ j1 = 0, j2 = 0, rational(~ i2, abs(j2)) + rational(~ i1, ~ j1) = rational(i1 * j2 + j1 * i2, j1 * j2)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
j1 < 0, j2 < 0 ⊦ j1 = 0, j2 = 0, rational(~ i1, ~ j1) + rational(~ i2, ~ j2) = rational(i1 * j2 + j1 * i2, j1 * j2)

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 → abs(i) = ~ i;