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Proof step 22 from proof add-eq (previous step)

(i * j0 + j * i0) * j1 = (i * j1 + j * i1) * j0, rational(i * j0 + j * i0, j * j0) = rational(i * j1 + j * i1, j * j1), 0 < j, 0 < j0, 0 < j1 ⊦ i0 * j1 = i1 * j0, rational(i0, j0) = rational(i1, j1), j0 = 0, j1 = 0, j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ i * (j + j0) = i * j + i * j0 subst: [i, j0, j] → [j1, j * i0, i * j0] rotate: F spec: int-mult inst: name: dist-rsplit

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ i * j = j * i; Used terms: j1, j * i0, i * j0