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Proof step 7 from proof add-eq (previous step)

∃ i, j. rj = rational(i, j) ∧ 0 < j, rational(i, j) + rj = rational(i, j) + rj0, 0 < j ⊦ rj = rj0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
rational(i, j) + rational(i0, j0) = rational(i, j) + rj0, 0 < j, 0 < j0 ⊦ rational(i0, j0) = rj0

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)