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Proof step 1 from proof add-zero (conclusion)

⊦ ri + 0r = ri

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ ri + rj = rational(ri.num * rj.denom + ri.denom * rj.num, ri.denom * rj.denom)

Rule argument

name: add-def rotate: F subst: [rj, ri] → [0r, ri]

Additional information

Used simplifier rules: zero-def: ⊦ 0r = rational(0, 1);%numerator-zero: ⊦ rational(0, j).num = 0;%denominator-zero: ⊦ rational(0, j).denom = 1;%make: ⊦ rational(ri.num, ri.denom) = ri;% ⊦ i * 0 = 0;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * j = j * i;% ⊦ 1 * i = i;% ⊦ i + 0 = i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used terms: 0r, ri