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Proof step 3 from proof denom-neg-01 (previous step)

¬(~ i ≠ 0 ∧ j ≠ 0) ⊦ rational(~ i, j).denom = rational(i, j).denom

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ i = 0, rational(~ i, 0).denom = 1

Rule argument

Additional information

Used simplifier rules: denominator-zero: ⊦ rational(0, j).denom = 1;%denominator-zero-den: ⊦ i ≠ 0 → rational(i, 0).denom = 1;% ⊦ ~ i = 0 ↔ i = 0;