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Proof step 11 from proof denom-neg-02 (previous step)

⊦ (rational(0, 1) - rational(0, 1)).denom = 1

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

name: sub-def-01 rotate: F subst: [j2, i2, j1, i1] → [1, 0, 1, 0]

Additional information

Used simplifier rules: add-zero-01: ⊦ rational(0, j1) + rational(i0, j0) = rational(i0, j0);%add-asso: ⊦ (ri + rj) + rj0 = ri + rj + rj0;%add-comm: ⊦ ri + rj = rj + ri;%denominator-zero: ⊦ rational(0, j).denom = 1; Used terms: 1, 0, 1, 0