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Proof step 20 from proof denom-neg-02 (previous step)

0 < 1 ∧ 0 < j, gcd(i, j) = 1, 0 < j ⊦ (rational(0, 1) + rational(~ i, j)).denom = j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 21:
⊦ rational(0, j1) + rational(i0, j0) = rational(i0, j0)
Proof step 22:
0 < 1 ∧ 0 < j, gcd(i, j) = 1, 0 < j ⊦ rational(~ i, j).denom = j

Rule argument

name: add-zero-01 rotate: F subst: [j0, i0, j1] → [j, ~ i, 1]

Additional information

Used terms: j, ~ i, 1