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Proof step 6 from proof denom-neg-02 (previous step)

⊦ (~ rational(0, 1)).denom = rational(0, 1).denom

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
⊦ (~ rational(0, 1)).denom = 1

Rule argument

Additional information

Used simplifier rules: denominator-zero: ⊦ rational(0, j).denom = 1;