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Proof step 12 from proof denom-not-zero (previous step)

abs(abs(i0)) < abs(gcd(i, i0)), gcd(i, i0) ≠ 0, abs(i0) ≠ 0, 0 ≤ gcd(i, i0), 0 = 0 ⊦ i = 0, i0 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ abs(abs(i)) = abs(i) subst: [i] → [i0] rotate: F spec: int-abs inst: name: abs-01

Additional information

Used terms: i0