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Proof step 9 from proof denom-pos-01 (previous step)

abs(i0) / gcd(i, i0) ≤ 0 ⊦ rational(i, i0).num = 0, i0 = 0, i = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ 0 < j → (i / j ≤ 0 ↔ i < j) subst: [j, i] → [gcd(i, i0), abs(i0)] rotate: F spec: int-div inst: name: div-lezero

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;% ⊦ gcd(i, j) ≤ 0 ↔ gcd(i, j) = 0;% ⊦ gcd(i, j) = 0 ↔ i = 0 ∧ j = 0; Used terms: gcd(i, i0), abs(i0)