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Proof step 5 from proof denom-pos (previous step)

i ≠ 0 ∧ i0 ≠ 0, abs(i0) / gcd(i, i0) < 0 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
abs(i0) / gcd(i, i0) < 0 ⊦ i0 = 0, i = 0

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)