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Proof step 4 from proof denum-same (previous step)

abs(rj.num) ≠ 0 ∧ rj.denom ≠ 0 ⊦ abs(rj.denom) / gcd(abs(rj.num), rj.denom) = rj.denom

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ abs(rj.denom) / gcd(abs(rj.num), rj.denom) = rj.denom, rj.num = 0

Rule argument

Additional information

Used simplifier rules: denom-not-zero: ⊦ ri.denom ≠ 0;% ⊦ abs(i) = 0 ↔ i = 0;