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Proof step 1 from proof div-def-01 (conclusion)

⊦ 0 < j ∧ 0 < j0 ∧ i0 ≠ 0 → rational(i, j) / rational(i0, j0) = rational(i * j0, j * i0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 < j, 0 < j0 ⊦ rational(i, j) / rational(i0, j0) = rational(i * j0, j * i0), i0 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)