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Proof step 15 from proof div-def-01 (previous step)

¬ i < 0, rational(abs(i), j) / rational(abs(i0), j0) = rational(abs(i) * j0, j * abs(i0)), 0 < j, 0 < j0 ⊦ i = 0, rational(i, j) / rational(i0, j0) = rational(i * j0, j * i0), i0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ i < j → ¬ j < i;% ⊦ ¬ i < j → (i ≠ j ↔ j < i);% ⊦ ¬ j < 0 → abs(j) = j;