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Proof step 32 from proof div-def-01 (previous step)

~ rational(i, j) / rational(abs(i0), j0) = rational(~(i * j0), j * abs(i0)), 0 < j, 0 < j0, i < 0 ⊦ i = 0, rational(i, j) / rational(i0, j0) = rational(i * j0, j * i0), i0 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 33:
⊦ rational(~ i, j) = ~ rational(i, j)
Proof step 34:
~ rational(i, j) / rational(abs(i0), j0) = ~ rational(i * j0, j * abs(i0)), 0 < j, 0 < j0, i < 0 ⊦ i = 0, rational(i, j) / rational(i0, j0) = rational(i * j0, j * i0), i0 = 0

Rule argument

name: negate-01 rotate: F subst: [j, i] → [j * abs(i0), i * j0]

Additional information

Used terms: j * abs(i0), i * j0