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Proof step 16 from proof div-neg-01 (previous step)

⊦ rj = 0r, rational(~(rj.denom * ri.num), rj.num * ri.denom) = ~(ri / rj), rj.num = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 17:
⊦ rational(~ i, j) = ~ rational(i, j)
Proof step 18:
⊦ rj = 0r, ~ rational(rj.denom * ri.num, rj.num * ri.denom) = ~(ri / rj), rj.num = 0

Rule argument

name: negate-01 rotate: F subst: [j, i] → [rj.num * ri.denom, rj.denom * ri.num]

Additional information

Used terms: rj.num * ri.denom, rj.denom * ri.num