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Proof step 4 from proof div-neg (previous step)

⊦ rj = 0r, rational((~ ri).num * rj.denom, (~ ri).denom * rj.num) = ~(ri / rj)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ ri / rj = rational(ri.num * rj.denom, ri.denom * rj.num)
Proof step 6:
⊦ rj = 0r, rational((~ ri).num * rj.denom, (~ ri).denom * rj.num) = ~ rational(ri.num * rj.denom, ri.denom * rj.num)

Rule argument

name: div-def rotate: F subst: [rj, ri] → [rj, ri]

Additional information

Used terms: rj, ri