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Proof step 2 from proof div-pos-def (previous step)

0 < i, 0 < i0, 0 < j, 0 < j0 ⊦ rational(i, j) / rational(i0, j0) = rational(i * j0, j * i0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ ri / rj = rational(ri.num * rj.denom, ri.denom * rj.num)
Proof step 4:
0 < i, 0 < i0, 0 < j, 0 < j0 ⊦ rational(rational(i, j).num * rational(i0, j0).denom, rational(i, j).denom * rational(i0, j0).num) = rational(i * j0, j * i0)

Rule argument

name: div-def rotate: F subst: [rj, ri] → [rational(i0, j0), rational(i, j)]

Additional information

Used terms: rational(i0, j0), rational(i, j)