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Proof step 13 from proof elim-sub (previous step)

0 < j1, 0 < j0, 0 < j ⊦ rational(i0, j0) = rational(i, j) + rational(~ i1, j1) ↔ rational(i, j) = rational(i0, j0) + rational(i1, j1)

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

Additional information