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Proof step 1 from proof equality-01 (conclusion)

rational(i, j) = rational(i0, j0), 0 < j, 0 < j0 ⊦ i * j0 = i0 * j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ ri = rj ↔ ri.num = rj.num ∧ ri.denom = rj.denom
Proof step 3:
rational(i, j).num = rational(i0, j0).num ∧ rational(i, j).denom = rational(i0, j0).denom, 0 < j, 0 < j0 ⊦ i * j0 = i0 * j

Rule argument

name: Equality rotate: F subst: [rj, ri] → [rational(i0, j0), rational(i, j)]

Additional information

Used terms: rational(i0, j0), rational(i, j)