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Proof step 5 from proof equality-01 (previous step)

i ≠ 0 ∧ j ≠ 0, rational(i, j).num = rational(i0, j0).num ∧ abs(j) / gcd(i, j) = rational(i0, j0).denom, 0 < j, 0 < j0 ⊦ i * j0 = i0 * j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: numerator-pos: ⊦ i ≠ 0 ∧ 0 < j → rational(i, j).num = i / gcd(i, j);% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ 0 < j → abs(j) = j;