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Proof step 4 from proof exrat-01 (previous step)

rational(i, j).num = i, rational(i, j).denom = j, 0 < j ⊦ ∃ i0, j0. rational(i, j) = rational(i0, j0) ∧ ¬ j0 ≤ 0

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: i, j

Additional information

Used simplifier rules: ⊦ i < j → (¬ ¬ j ≤ i ↔ false); Used terms: i, j