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Proof step 1 from proof exrat (conclusion)

⊦ ∃ i, j. ri = rational(i, j) ∧ ri.num = i ∧ ri.denom = j ∧ 0 < j

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: make: ⊦ rational(ri.num, ri.denom) = ri;%denom-pos-01: ⊦ ¬ rj.denom ≤ 0;% ⊦ ¬ i < j ↔ j ≤ i;