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Proof step 2 from proof factor-rat-02 (previous step)

0 < j ⊦ rational(i1 * i, i1 * j) = rational(i, j), i1 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ 0 < j ∧ 0 < i1 → rational(i1 * i, i1 * j) = rational(i, j)
Proof step 4:
¬(0 < j ∧ 0 < i1), 0 < j ⊦ rational(i1 * i, i1 * j) = rational(i, j), i1 = 0

Rule argument

name: factor-rat-03 rotate: F subst: [j, i, i1] → [j, i, i1]

Additional information

Used terms: j, i, i1