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Proof step 1 from proof int-mult (conclusion)

⊦ rational(i, 1) * rational(j, 1) = rational(i * j, 1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ ri * rj = rational(ri.num * rj.num, ri.denom * rj.denom)
Proof step 3:
⊦ rational(rational(i, 1).num * rational(j, 1).num, rational(i, 1).denom * rational(j, 1).denom) = rational(i * j, 1)

Rule argument

name: mult-def rotate: F subst: [rj, ri] → [rational(j, 1), rational(i, 1)]

Additional information

Used terms: rational(j, 1), rational(i, 1)