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Proof step 11 from proof int-mult (previous step)

¬(j ≠ 0 ∧ 0 < 1) ⊦ i = 0, rational(rational(j, 1).num * i, rational(i, 1).denom * rational(j, 1).denom) = rational(i * j, 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
⊦ i = 0, rational(0, rational(i, 1).denom) = rational(0, 1)

Rule argument

Additional information

Used simplifier rules: numerator-zero: ⊦ rational(0, j).num = 0;%denominator-zero: ⊦ rational(0, j).denom = 1;% ⊦ 1 * i = i;% ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * 0 = 0;