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Proof step 12 from proof make (previous step)

⊦ ¬ i0 ≤ 0, rational(rational(i, i0).num, rational(i, i0).denom).num = rational(i, i0).num ∧ rational(rational(i, i0).num, rational(i, i0).denom).denom = rational(i, i0).denom, ¬ i ≤ 0 ∧ ¬ 0 ≤ i0, ¬ 0 ≤ i ∧ ¬ 0 ≤ i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward)% ⊦ i ≤ j → (j ≤ i ↔ i = j);