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Proof step 18 from proof make (previous step)

⊦ i = 0, rational(rational(i, 0).num, 1).num = rational(i, 0).num ∧ rational(rational(i, 0).num, 1).denom = 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 19:
⊦ i ≠ 0 → rational(i, 0).num = i
Proof step 20:
i ≠ 0 ⊦ i = 0, rational(i, 1).num = i ∧ rational(i, 1).denom = 1

Rule argument

name: numerator-zero-den rotate: F subst: [i] → [i]

Additional information

Used terms: i