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Proof step 2 from proof make (previous step)

⊦ rational(rational(i, i0).num, rational(i, i0).denom) = rational(i, i0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ ri = rj ↔ ri.num = rj.num ∧ ri.denom = rj.denom
Proof step 4:
⊦ rational(rational(i, i0).num, rational(i, i0).denom).num = rational(i, i0).num ∧ rational(rational(i, i0).num, rational(i, i0).denom).denom = rational(i, i0).denom

Rule argument

name: Equality rotate: F subst: [rj, ri] → [rational(i, i0), rational(rational(i, i0).num, rational(i, i0).denom)]

Additional information

Used terms: rational(i, i0), rational(rational(i, i0).num, rational(i, i0).denom)