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Proof step 41 from proof make (previous step)

¬(~(i / gcd(i, i0)) ≠ 0 ∧ 0 < ~(i0 / gcd(i, i0))), 0 < i, i0 < 0 ⊦ i0 = 0, i = 0, rational(~(i / gcd(i, i0)), ~(i0 / gcd(i, i0))).num + i / gcd(i, i0) = 0 ∧ i0 / gcd(i, i0) + rational(~(i / gcd(i, i0)), ~(i0 / gcd(i, i0))).denom = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ i0 < 0 → ¬ 0 ≤ i0 / gcd(i, i0);% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ 0 < ~ i ↔ i < 0;% ⊦ i ≠ 0 → i / gcd(i, i0) ≠ 0;% ⊦ ~ i = 0 ↔ i = 0;