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Proof step 49 from proof make (previous step)

i ≠ 0 ∧ i0 ≠ 0, 0 < i0 ⊦ i = 0, rational(i / gcd(i, i0), abs(i0) / gcd(i, i0)).num = i / gcd(i, i0) ∧ rational(i / gcd(i, i0), abs(i0) / gcd(i, i0)).denom = abs(i0) / gcd(i, i0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ 0 < j → abs(j) = j;