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Proof step 19 from proof mult-ass (previous step)

0 < j, 0 < j0, 0 < j1 ⊦ j0 = 0, rational((i * i0) * i1, (j * j0) * j1) = rational(i, j) * rational(i0 * i1, j0 * j1), j = 0, j1 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

name: mult-def-03 rotate: F subst: [j2, i2, j1, i1] → [j0 * j1, i0 * i1, j, i]

Additional information

Used simplifier rules: ⊦ 0 < i → (i * j = 0 ↔ j = 0);% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * j = j * i; Used terms: j0 * j1, i0 * i1, j, i