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Proof step 15 from proof mult-def-03 (previous step)

0 < j1, j2 < 0 ⊦ j2 = 0, rational(~(i2 * i1), ~(j2 * j1)) = rational(i1 * i2, j1 * j2)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 16:
⊦ j ≠ 0 → rational(~ i, ~ j) = rational(i, j)

Rule argument

name: neg-neg rotate: F subst: [j, i] → [j2 * j1, i2 * i1]

Additional information

Used simplifier rules: ⊦ 0 < i → (i * j = 0 ↔ j = 0);% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * j = j * i; Used terms: j2 * j1, i2 * i1