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Proof step 9 from proof mult-def-03 (previous step)

j2 < 0, 0 < j1, j2 < 0 ⊦ rational(i1, j1) * rational(~ i2, abs(j2)) = rational(i1 * i2, j1 * j2), j2 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: neg-neg: ⊦ j ≠ 0 → rational(~ i, ~ j) = rational(i, j);% ⊦ i < 0 → abs(i) = ~ i;