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Proof step 5 from proof mult-one (previous step)

∃ i, j. ri = rational(i, j) ∧ 0 < j ⊦ ri * rational(1, 1) = ri

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
0 < j ⊦ rational(i, j) * rational(1, 1) = rational(i, j)

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)