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Proof step 2 from proof neg-neg (previous step)

⊦ j = 0, rational(~ i, ~ j) = rational(i, j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ ri = rj ↔ ri.num = rj.num ∧ ri.denom = rj.denom
Proof step 4:
⊦ j = 0, rational(~ i, ~ j).num = rational(i, j).num ∧ rational(~ i, ~ j).denom = rational(i, j).denom

Rule argument

name: Equality rotate: F subst: [rj, ri] → [rational(i, j), rational(~ i, ~ j)]

Additional information

Used terms: rational(i, j), rational(~ i, ~ j)