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Proof step 19 from proof negate-01 (previous step)

0 < abs(j), j < 0, j < 0, j < 0 ⊦ j = 0, rational(i, abs(j)) = ~ ~ rational(i, abs(j))

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

name: negate-02 rotate: F subst: [ri] → [rational(i, abs(j))]

Additional information

Used terms: rational(i, abs(j))