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Proof step 14 from proof negate (previous step)

0 < j ⊦ rational(~ rational(i, j).num, rational(i, j).denom).num + rational(i, j).num = 0 ∧ rational(i, j).denom = rational(~ rational(i, j).num, rational(i, j).denom).denom

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 15:
⊦ rational(~ i, j).num = ~ rational(i, j).num
Proof step 16:
0 < j ⊦ ~ rational(rational(i, j).num, rational(i, j).denom).num + rational(i, j).num = 0 ∧ rational(i, j).denom = rational(~ rational(i, j).num, rational(i, j).denom).denom

Rule argument

name: num-neg-01 rotate: F subst: [j, i] → [rational(i, j).denom, rational(i, j).num]

Additional information

Used terms: rational(i, j).denom, rational(i, j).num