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Proof step 1 from proof num-div-denom (conclusion)
⊦ i1 ≠ 0 → rational(i, i1).num / rational(i, i1).denom = i / i1
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
⊦ i1 = 0, rational(i, i1).num / rational(i, i1).denom = i / i1
Rule argument
Additional information