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Proof step 2 from proof num-neg-01 (previous step)

⊦ rational(i, j).num + rational(~ i, j).num = 0

User applied rule cut formula

And obtained the following new goals

Proof step 3:
j = 0 ⊦ rational(i, j).num + rational(~ i, j).num = 0
Proof step 13:
⊦ j = 0, rational(i, j).num + rational(~ i, j).num = 0

Rule argument

fma: j = 0

Additional information

Used formulas: j = 0