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Proof step 8 from proof num-neg-01 (previous step)

⊦ rational(i, 1).num + rational(~ i, 1).num = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ i ≠ 0 ∧ 0 < j → rational(i, j).num = i / gcd(i, j)
Proof step 10:
i ≠ 0 ∧ 0 < 1 ⊦ i / gcd(i, 1) + rational(~ i, 1).num = 0

Rule argument

name: numerator-pos rotate: F subst: [j, i] → [1, i]

Additional information

Used simplifier rules: numerator-zero: ⊦ rational(0, j).num = 0; Used terms: 1, i