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Proof step 1 from proof num-same-01 (conclusion)
⊦ rational(abs(ri.num), ri.denom).num = abs(ri).num
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 2
:
⊦ abs(ri) = rational(abs(ri.num), ri.denom)
Rule argument
name: abs-def rotate: F subst: [ri] → [ri]
Additional information
Used terms: ri