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Proof step 5 from proof one (previous step)

i < 0 ⊦ rational(i, i) = rational(1, 1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ j < 0 → rational(i, j) = rational(~ i, abs(j))
Proof step 7:
i < 0, i < 0 ⊦ rational(~ i, abs(i)) = rational(1, 1)

Rule argument

name: denom-neg rotate: F subst: [j, i] → [i, i]

Additional information

Used terms: i, i