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Proof step 1 from proof sub-def-01 (conclusion)

⊦ 0 < j1 ∧ 0 < j2 → rational(i1, j1) - rational(i2, j2) = rational(i1, j1) + rational(~ i2, j2)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 < j1, 0 < j2 ⊦ rational(i1, j1) - rational(i2, j2) = rational(i1, j1) + rational(~ i2, j2)

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)