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Proof step 3 from proof list2set-append (
previous step
)
∀ y. list2set(x0 + y) = list2set(x0) ∪ list2set(y) ⊦ list2set(x0 + y) ++ a = (list2set(x0) ∪ list2set(y)) ++ a
User applied rule all left
And closed the goal!
Rule argument
pos: left 1 terms: y abort: F discard: T computed: F
Additional information
Used simplifier rules: ⊦ s ∪ s0 = s0 ∪ s; Used terms: y