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Proof step 1 from proof ins-same (conclusion)

⊦ stng[a, stng[a]] = stng

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ stng[a, stng[a]][a0] = stng[a0]

Rule argument

Additional information

Used simplifier rules: Extension: ⊦ stng1 = stng2 ↔ (∀ a. stng1[a] = stng2[a]);