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Proof step 5 from proof ins-two (previous step)

⊦ a0 = a, stng[b, d0][a0] = stng[a, d][b, d0][a0], a = b

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ a ≠ b → stng[b, d][a] = stng[a]

Rule argument

name: At-other rotate: F subst: [a, d, b, stng] → [a0, d0, b, stng]

Additional information

Used simplifier rules: At-same: ⊦ stng[a, d][a] = d;%At-other: ⊦ a ≠ b → stng[b, d][a] = stng[a]; Used terms: a0, d0, b, stng